\(\frac{\left(\frac{5}{8}+\frac{5}{27}-\frac{5}{49}\right)\cdot8\cdot27\cdot49}{\left(\frac{11}{8}+\frac{11}{27}-\frac{11}{49}\right)\cdot8\cdot27\cdot49}+\frac{6}{11}\)
\(=\frac{8+27-49}{8+27-49}+\frac{6}{11}\)
\(=1+\frac{6}{11}\)
\(=\frac{11}{11}+\frac{6}{11}=\frac{17}{11}\)
\(\frac{\frac{5}{8}+\frac{5}{27}-\frac{5}{49}}{\frac{11}{8}+\frac{11}{27}-\frac{11}{49}}+\frac{6}{11}\)
\(=\frac{5\left(\frac{1}{8}+\frac{1}{27}-\frac{1}{49}\right)}{11\left(\frac{1}{8}+\frac{1}{27}-\frac{1}{49}\right)}+\frac{6}{11}\)
\(=\frac{5}{11}+\frac{6}{11}=\frac{11}{11}=1\)
Chép lại đề bài!
\(=\frac{5.(\frac{1}{8}+\frac{1}{27}-\frac{1}{49})}{11.(\frac{1}{8}+\frac{1}{27}-\frac{1}{49})}+\frac{6}{11}\)
\(=\frac{5}{11}+\frac{6}{11}\)
\(=\frac{11}{11}=1\)
