Question

Tính M_B biết

a)d_SO2/B =32

B)d_Co2/B=1,375

C)d_cl2/B=1,61

D)d_SO3/B= 1,25

Answer 1

\(a,d_{SO_2/B}=32\\ \Rightarrow d_{SO_2/B}=\frac{M_{SO_2}}{M_B}\\ \Rightarrow32=\frac{64}{M_B}\\ \Rightarrow M_B=\frac{64}{32}=2\)

\(b,d_{CO_2/B}=1,375\\ \Rightarrow d_{CO_2/B}=\frac{M_{CO_2}}{M_B}\\ \Rightarrow1,375=\frac{44}{M_B}\\ \Rightarrow M_B=\frac{44}{1,375}=32\left(g/mol\right)\)

\(c,d_{Cl_2/B}=1,61\\ \Rightarrow d_{Cl_2/B}=\frac{M_{Cl_2}}{M_B}\\ \Rightarrow1,61=\frac{71}{M_B}\\ \Rightarrow M_B=\frac{71}{1,61}\approx44\left(g/mol\right)\)

\(d,d_{SO_3/B}=1,25\\ \Rightarrow d_{SO_3/B}=\frac{M_{SO_3}}{M_B}\\ \Rightarrow1,25=\frac{80}{M_B}\\ \Rightarrow M_B=\frac{80}{1,25}=64\left(g/mol\right)\)