Ta có : m=2016.(1+1/1.3)(1+1/2.4)(1+1/3.5)....(1+1/2014.2016)
=2016.(4/1.3)(9/2.4)(16/3.5)...(4060225/2014.2016)
=2016(2.2/1.3)(3.3/2.4)(4.4/3.5)...(2015.2015/2014.2016)
=2016(2.3.4.....2015/2.3.4....2015)(2.3.4.....2015/3.4.5.....2016)
=2016(1.2/2016)
=2016.1/1008
=2
Vậy m=2
k đúng cho mình nha ! Nếu đúng thì 3K nhé
tính :(1+1/1.3).(1+1/2.4)+(1+1/3.5)+...+(1+1/2014.2016)
C=(1+1/1.3)(1+1/2.4)(1+1/3.5)......(1+1/2014.2016)
c= (1+1/1.3).(1+1/2.4).(1+1/3.5)*...*(1+1/2014.2016)
A=2016.(1+1/1.3).(1+1/2.4).(1+1/3.5)...(1+1/2014.2016)
\(\frac{\left(1.3+1\right)\left(2.4+1\right)\left(3.5+1\right).......\left(2014.2016+1\right)}{1.3.2.4.3.5...............2014.2016}\)
Tính:
\(\left(1+\frac{1}{1.3}\right)\left(1+\frac{1}{2.4}\right)\left(1+\frac{1}{3.5}\right)...\left(1+\frac{1}{2014.2016}\right)\)
Tính:
C=\(\left(1+\frac{1}{1.3}\right)\left(1+\frac{1}{2.4}\right)\left(1+\frac{1}{3.5}\right)...\left(1+\frac{1}{2014.2016}\right)\)
Tính C:
C = ( 1+1/1.3)(1+1/2.4)(1+1/3.5).....(1+1/2014.2016)
(Mình đang rất vội nên mong các bạn trả lời sớm. Cảm ơn nhiều!)
Tính
B=2016.\(\left(1+\frac{1}{1.3}\right).\left(1+\frac{1}{2.4}\right).\left(1+\frac{1}{3.5}\right)............\left(1+\frac{1}{2014.2016}\right)\)
