Đặt \(A=\frac{240\cdot50+48\cdot50}{42\cdot37+21\cdot126}=\frac{48\cdot5\cdot50+48\cdot50}{21\cdot2\cdot37+21\cdot126}\)
\(\Rightarrow A=\frac{48\cdot250+48\cdot50}{21\cdot74+21\cdot126}=\frac{48\cdot\left(250+50\right)}{21\cdot\left(74+126\right)}\)
\(\Rightarrow A=\frac{48\cdot300}{21\cdot300}=\frac{48}{21}=\frac{16}{7}\)