tính vế trên trước: 2^12 x 3^5 - 4^6 x 9^2 = 4096 x 243 - 4096 x 81 = 4096 x ( 243 - 81 ) = 663552.
tính vế dưới sau : ( 2^2 x 3 )^6 + 8^4 x 3^5 = ( 4 x 3 )^6 + 4096 x 243 = 12^6 + 995328 = 2985984 + 995328 = 3981312.
Vậy được: 663552/3981312 = 1/6.
Tính :
a) \(\frac{2^{12}x3^5-4^6x9^2}{\left(2^2x3\right)^6+8^4x3^5}\)
b) \(\frac{1}{9x10}\)\(-\)\(\frac{1}{8x9}\)\(-\)\(\frac{1}{7x8}\)\(-\)\(\frac{1}{6x7}\)\(-\)\(\frac{1}{5x6}\)\(-\)\(\frac{1}{4x5}\)\(-\)\(\frac{1}{3x4}\)\(-\)\(\frac{1}{2x3}\)\(-\)\(\frac{1}{1x2}\)
c) \(\frac{1}{2}:\left(-1\frac{1}{2}\right):1\frac{1}{3}:\left(-1\frac{1}{4}\right):1\frac{1}{5}:\left(-1\frac{1}{6}\right):.....:\left(-1\frac{1}{100}\right)\)
Làm đc phần nào thì gúp mk với . ToT
Tính B=\(\frac{\left(\frac{2}{3}\right)^3.\left(\frac{-3}{4}\right)^2.\left(-1\right)^5}{\left(\frac{2}{5}\right)^2.\left(\frac{5}{12}\right)^2}-\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
giúp mình giải chi tiết nha các bạn mai mình phải nộp rồi
thực hiện các phép tính sau:
\(a,\left(4\frac{5}{37}-3\frac{4}{5}+8\frac{15}{29}\right)-\left(3\frac{5}{37}-6\frac{14}{29}\right)\)
\(b,\left(2\frac{5}{6}+1\frac{4}{9}\right):\left(10\frac{1}{12}-9\frac{1}{2}\right)\)
\(c,-\frac{2}{3}\left(8\frac{1}{2}-7.75\right):\frac{1}{3}+0.125:2\frac{2}{3}\)
\(\left(\frac{3}{8}+\frac{-3}{4}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)
\(\frac{1}{2}+\frac{3}{4}-\left(\frac{3}{4}-\frac{4}{5}\right)\)
\(6\frac{5}{12}:2\frac{3}{4}+11\frac{1}{4}\left(\frac{1}{3}-\frac{1}{5}\right)\)
\(\left(\frac{7}{8}-\frac{3}{4}\right)1\frac{1}{3}-\frac{2}{7}\left(3,5\right)^2\)
\(\left(\frac{3}{5}+0,415-\frac{3}{200}\right)2\frac{2}{3}.0,25\)
Thực hiện các phép tính
cảm ơn
Thực hiện phép tính:
a) \(A=\frac{5.\left(2^2.3^2\right)^9.\left(2^2\right)^6-2.\left(2^2.3\right)^{14}.3^4}{5.2^{28}.3^{18}-7.2^{29}.3^{18}}\)
b) \(B=81.\left[\frac{12-\frac{12}{7}-\frac{12}{289}-\frac{12}{85}}{4-\frac{4}{7}-\frac{4}{289}-\frac{4}{85}}:\frac{5+\frac{5}{13}+\frac{5}{169}+\frac{5}{91}}{6+\frac{6}{13}+\frac{6}{169}+\frac{6}{91}}\right].\frac{158158158}{711711711}\)
Tính giá trị của biểu thức P = \(\left[2\frac{11}{25}-0,84.\left[6\frac{8}{9}:2\frac{7}{12}-\frac{5}{12}.4\frac{4}{35}\right]\right]:\left[7,605:7\frac{1}{2}+3,086\right]\)
tính\(\frac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}-\frac{5^{10}.7^3-25^2.49^2}{\left(125.7\right)^3+5^9.14^3}\)
Bài 12 : Tính
a) \(\left(\frac{-10}{3}\right)^2.\frac{\left(-6\right)^4}{5}\)
b) \(\left(\frac{3}{4}\right)^3:\left(\frac{3}{4}\right)^2:\left(\frac{2}{3}\right)^2\)
c) \(\frac{4^6.9^5+6^6.120}{8^4.3^{12}-6^{11}}\)
tính
A=\(\frac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}\)- \(\frac{5^{10}.7^{3-25^5.49^2}}{\left(\left(125.7\right)^3\right)+5^9.14^3}\)
