3 x 7/10 + 7/10 x 5 + 2 x 14/20
=3x7/10+7/10x5+2x7/10
=7/10x(3+5+2)
=7/10x10
=7
ta có
\(3\cdot\frac{7}{10}+\frac{7}{10}\cdot5+2\cdot\frac{14}{20}\)
\(=3\cdot\frac{7}{10}+\frac{7}{10}\cdot5+2\cdot\frac{7}{10}\)
\(=\frac{7}{10}\cdot\left(3+5+2\right)\)
\(=\frac{7}{10}\cdot10\)
\(=\frac{70}{10}=7\)
chúc bạn hok tốt!
3x7/10+7/10x5+2x14/20
=3x7/10+7/10x5+2x7/10
=7/10x(3+5+2)
=7/10x 10
=70/10
=7