Tính tổng :
A = \(\left(1-\frac{1}{1+2}\right)\left(1-\frac{1}{1+2+3}\right)\left(1=\frac{1}{1+2+3+4}\right).....\left(1=\frac{1}{1+2+3+...+1986}\right)\)
thực hiện phép tính
\(A=\left(1-\frac{1}{2}\right)\left(1-\frac{1}{1+2+3}\right).....\left(1-\frac{1}{1+2+3+...+1986}\right)\)
Bài 1 :
a) \(\frac{1}{1.2}\)+ \(\frac{1}{2.3}\)+.....+ \(\frac{1}{a\left(a+1\right)}\)
b) \(\frac{1}{1.2.3}+\frac{1}{2.3.4}+.....+\frac{1}{a\left(a+1\right).\left(a+2\right)}\)
\(F=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{\left(n-1\right)n}=\frac{n-1}{n}\)
\(G=\frac{1}{1.2.3}+\frac{1}{2.3.4}+\frac{1}{3.4.5}+...+\frac{1}{\left(n-1\right)\left(n-1\right).n}=\)
\(H=2+4+6+..+2n=\)
tính: \(\frac{1}{1.2.3}+\frac{1}{2.3.4}+\frac{1}{3.4.5}+...+\frac{1}{a\left(a+1\right)\left(a+2\right)}\)
Tính hợp lý
a) A = \(\left(1-\frac{1}{1.2}\right)+\left(1-\frac{1}{2.3}\right)+...+\left(1-\frac{1}{2016.2017}\right)\)
\(\left|x+\frac{1}{1.2}\right|+\left|x+\frac{1}{2.3}\right|+\left|x+\frac{1}{3.4}\right|+...+\left|x+\frac{1}{99.100}\right|=100x\)
\(A=1.2+2.3+...+n\left(n+1\right)\)
\(\Rightarrow3A=1.2.3+2.3.3+...+n\left(n+1\right)3\)
\(=1.2.3+2.3.\left(4-1\right)+...+n\left(n+1\right)\left[\left(n+2\right)-\left(n-1\right)\right]\)
\(=1.2.3+2.3.4-1.2.3+...+n\left(n+1\right)\left(n+2\right)-\left(n-1\right)n\left(n+1\right)\)
\(=n\left(n+1\right)\left(n+2\right)\)
\(\Rightarrow A=\frac{n\left(n+1\right)\left(n+2\right)}{3}\)
tính
A = \(\frac{3}{\left(1.2\right)^2}+\frac{5}{\left(3.2\right)^2}+.....+\frac{2n+1}{\left[n.\left(n+1\right)\right]^2}\)