Question

Tính:

 a.\(\frac{1}{7}+x=\frac{68}{35}\)

b.\(\frac{997}{3304}-x=\frac{15}{56}\)

Answer 1

a. \(\frac{1}{7}\)+ X = \(\frac{68}{35}\)

               X = \(\frac{68}{35}\)-\(\frac{1}{7}\)

               X =  \(\frac{9}{5}\). Vậy X = \(\frac{9}{5}\)

b. \(\frac{997}{3304}\)- X = \(\frac{15}{56}\)

                    X = \(\frac{997}{3304}\)- \(\frac{15}{56}\)

                   X = \(\frac{2}{59}\). Vậy X = \(\frac{2}{59}\)

Answer 2

a. \(\frac{1}{7}+x=\frac{68}{35}\)

             \(x=\frac{68}{35}-\frac{1}{7}\)

              \(x=\frac{68}{35}-\frac{5}{35}\)

             \(x=\frac{9}{5}\)

Vậy       \(x=\frac{9}{5}\)

*** mk nha

Answer 3

a.\(\frac{1}{7}+x=\frac{68}{35}\)

              \(x=\frac{68}{35}-\frac{1}{7}\) 

              \(x=\frac{9}{5}\)

b.\(\frac{997}{3304}-x=\frac{15}{56}\)

                     \(x=\frac{997}{3304}-\frac{15}{56}\)

                   \(x=\frac{2}{59}\)

Answer 4

\(a.\frac{1}{7}+x=\frac{68}{35}\)

              \(x=\frac{68}{35}-\frac{1}{7}\)

              \(x=\frac{68}{35}-\frac{5}{35}\)

              \(x=\frac{63}{35}=\frac{9}{5}\)

\(b.\frac{997}{3304}-x=\frac{15}{56}\)

                     \(x=\frac{997}{3304}-\frac{15}{56}\)

                     \(x=\frac{997}{3304}-\frac{885}{3304}\)

                     \(x=\frac{112}{3304}=\frac{2}{59}\)