\(\frac{7}{5}+\frac{4}{7}-\frac{9}{10}=\frac{98}{70}+\frac{40}{70}-\frac{63}{70}=\frac{98+40-63}{70}=\frac{75}{70}=\frac{15}{14}\)
7\5+4\7-9\10=49\35+20\35-9\10=69\35-9\10=138\70-63\70=75\70=15\14
\(\frac{7}{5}+\frac{4}{7}-\frac{9}{10}=\frac{49}{35}+\frac{20}{35}-\frac{9}{10}\)
\(=\frac{69}{35}-\frac{9}{10}=\frac{690}{350}-\frac{315}{350}=\frac{375}{350}=\frac{15}{14}\)