Question

Tìm x,y,z:

a) \(\frac{6}{11}x=\frac{9}{2}y=\frac{18}{5}z\) và \(-x+y+z=-120\)

b)\(\frac{x}{12}=\frac{y}{9}=\frac{z}{5}\) và \(x.y.z=20\)

Đang cần gấp !!!

Answer 1

\(\frac{6}{11}x=\frac{9}{2}y=\frac{18}{5}z\Rightarrow\frac{6x}{11.18}=\frac{9y}{2.18}=\frac{18z}{5.18}\)

\(\Rightarrow\frac{-x}{-33}=\frac{y}{4}=\frac{z}{5}=\frac{-x+y+z}{-33+4+5}=\frac{-120}{-24}=5\)

\(\Rightarrow x=165;y=20;z=25\)