`xy -2x =0`
`<=> x(y-2) =0`
`<=> {(x=0),(y=2):}`
Vậy `x,y in {0;2}`
`xy-2x=0`
`=> x(y-2)=0`
`=>` \(\left[{}\begin{matrix}x=0\\y-2=0\end{matrix}\right.\)
`=>` \(\left[{}\begin{matrix}x=0\\y=2\end{matrix}\right.\)
\(xy-2x< =>x\left(y-2\right)=0< =>\left\{{}\begin{matrix}x=0\\y-2=0\end{matrix}\right.< =>\left\{{}\begin{matrix}x=0\\y=2\end{matrix}\right.\)
`xy-2=0`
`=>x(y-2)=0`
`@` TH `1:x=0`
`@`TH `2:y-2=0`
`=>y=2`
xy-2x=0
x(y-2)=0
Ta có 2 TH
TH1: x=0
TH2:y-2=0 \(\Rightarrow y=0+2=2\)
Vậy:..............
xy−2x=0xy-2x=0
⇔x(y−2)=0⇔x(y-2)=0
⇔{x=0y=2⇔{x=0y=2
Vậy x,y∈{0;2}x,y∈{0;2}