\(\frac{2x+1}{5}=\frac{3y-2}{7}=\frac{2x+3y-1}{6x}=\)
\(=\frac{2x+1+3y-2-2x-3y+1}{5+7-6x}=0\)
\(\Rightarrow\frac{2x+1}{5}=0\Rightarrow x=-\frac{1}{2}\)
\(\Rightarrow\frac{3y-2}{7}=0\Rightarrow y=\frac{2}{3}\)
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