Vì `|x|+|x+1|+|x+2|>=0`
`=>6x>=0`
`=>x>=0`
`=>|x|=x,|x+1|=x+1,|x+2|=x+2`
`pt<=>x+x+1+x+2=6x`
`<=>3x+3=6x`
`<=>3=3x`
`<=>x=1(tmđk)`
Vậy `x=1`
Vì |x| + |x+1| + |x+2| \(\ge\) 0 với \(\forall\)x \(\Rightarrow\) 6x \(\ge\) 0 \(\Rightarrow\) x \(\ge\) 0
\(\Rightarrow\) x + x + 1 + x + 2 = 6x
\(\Rightarrow\) 3x + 3 = 6x
\(\Rightarrow\) 3x = 3
\(\Rightarrow\) x = 1
Vậy x = 1
Giải:
\(\left|x\right|+\left|x+1\right|+\left|x+2\right|=6x\)
Ta có:
\(\left|x\right|+\left|x+1\right|+\left|x+2\right|\ge0\) (do mỗi số hạng đều \(\ge0\) )
\(\Rightarrow6x\ge0\)
\(\Rightarrow x\ge0\)
Vì \(x\ge0\)
\(\Rightarrow x+x+1+x+2=6x\)
\(\Rightarrow3x+3=6x\)
\(\Rightarrow3x-6x=-3\)
\(\Rightarrow-3x=-3\)
\(\Rightarrow x=-3:-3\)
\(\Rightarrow x=1\)
Chúc bạn học tốt!
