\(\left(x-5\right)\left(x-4\right)-\left(x+1\right)\left(x-2\right)=7\)
\(\Leftrightarrow\left(x-5\right).x-\left(x-5\right).4-x.\left(x-2\right)-\left(x-2\right)=7\)
\(\Leftrightarrow x^2-5x-4x+20-x^2+2x-x+2=7\)
\(\Leftrightarrow-8x+22=7\)
\(\Leftrightarrow-8x=-15\)
\(\Leftrightarrow x=\frac{15}{7}\)
Vậy ...
tìm x biết : 4x(x-1) - 3(x^2 - 5) - x^2 = (x-3) -(x+4). giải giúp mik vs ạ
tìm x bik
a) (8x-3)(3x+2)- (4x+7)(x+4)=(2x+1)(5x-1)
b) (8-5x)(x+2) + 4(x-2)(x+1)+2(x-2)(x+2) = 0
c) 4 ( x-1)(x+5) - (x+2)(x+5) = 3(x-1)(x+2).
giúp vs ạ
Tìm x biết:
a) (x+5).(2x+1)=0
b) x.(x+2)-3.(x+2)=0
c) 2x.(x-5)-x.(3+2x)=26
d) x2-10x-8x+16=0
e) x2-10x=25
f) 5x.(x-1)=x-1
g) 2.(x+5)-x2-5x=0
h) x2+5x-6=0
i) (2x-3)2-4.(x+1).(x-1)=49
j) x3+x2+x+1=0
k) x3-x2=4x2-8x+4
Mn ơi giúp em vs ạ,em cảm ơn trc ạ
Tìm x:
a,(3x+2)*(2x+9)-(x+3)*(6x+1)=(x+1)2-(x+2)*(x-2)
b,(2x+3)*(x-4)+(x-5)*(x-2)=(3x-5)*(x-4)
c,(x+2)3-(x-2)3-12x*(x-1)=-8
d,(3x-1)2-5*(x+1)+6x-3*2x+1-(x-1)2=16
Mn giúp mk vs ạ! mk đang rất cần ~~! Cảm ơn trc ạ!
\(\dfrac{5}{x+2}-\dfrac{x-1}{x-2}=\dfrac{12}{x^2-4}+1\)
giúp vs ạ mik đng cần gấp
\(8(x+\dfrac{1}{x} )^{2} \)\(+4(x^{2}+\dfrac{1}{x^{2} } )^{2}\)\(-4 (x^{2}+\dfrac{1}{x^{2}} )(x+\dfrac{1}{x})^{2} \)\(=(x+4)^{2}\)
giúp mik vs ạ cho mik cách giải pt này vs ạ
( 2/3 x) . (9x/2 +1/4 ) -(3x^2 +x +2 ) = 3
giúp vs bài này tìm x gấp lắm ạ
2(x-1)(x+5) - 4x + 4 = 0
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