Question

Tìm x\(\in\)Q biết:

a,\(\frac{2}{3x}-\frac{3}{12}=\frac{4}{5}-\left(\frac{7}{x}-2\right)\)

b,\(\left(\frac{3}{2}-\frac{2}{-5}\right):x-\frac{1}{2}=\frac{3}{2}\)

Answer 1

a) \(\frac{2}{3x}-\frac{3}{12}=\frac{4}{5}-\left(\frac{7}{x}-2\right)\)

\(\frac{2}{3x}+\left(\frac{7}{x}-2\right)=\frac{4}{5}+\frac{3}{12}\)

\(\frac{2}{3x}+\frac{7}{x}-2=\frac{21}{20}\)

\(\frac{2}{3x}+\frac{7}{x}=\frac{61}{20}\)

\(\frac{2}{3x}+\frac{21}{3x}=\frac{61}{20}\)

\(\frac{23}{3x}=\frac{61}{20}\)

\(3x=\frac{460}{61}\)

\(x=\frac{460}{183}\)

b) \(\left(\frac{3}{2}-\frac{2}{-5}\right):x-\frac{1}{2}=\frac{3}{2}\)

\(\frac{19}{10}:x-\frac{1}{2}=\frac{3}{2}\)

\(\frac{19}{10}:x=2\)

\(x=\frac{19}{20}\)

Answer 2

Thanks bạn nhìu