1/4x = 3/4 - 5/6
1/4x = -1/12
x = -1/12 : 1/4
x = -1/3
3/4 - 1/4x= 5/6
1/4x=3/4-5/6
1/4x= -1/12
x = -1/12 : 1/4
x = -1/3
Bài 4. Tìm x biết:
a. \(\dfrac{x}{5}=\dfrac{2}{5},\dfrac{3}{8}=\dfrac{6}{x},\dfrac{1}{9}=\dfrac{x}{27}\)
b. \(\dfrac{4}{x}=\dfrac{8}{6},\dfrac{3}{x-5}=\dfrac{-4}{x+2},\dfrac{x}{-2}=\dfrac{-8}{x}\)
\(\dfrac{x}{3}-\dfrac{1}{4}=\dfrac{-5}{6}\)
\(\dfrac{2x}{3}=\dfrac{6}{x}\)
\(\dfrac{x-1}{14}=\dfrac{4}{x}\)
\(\dfrac{-x}{8}=\dfrac{-50}{x}\)
Tìm x
Tìm x biết :
\(x+\dfrac{1}{2}=\dfrac{33}{4}\)
\(\dfrac{5}{6}-x=\dfrac{1}{3}\)
\(x+\dfrac{4}{5}=\dfrac{-2}{3}\)
Tìm x, y, z, t ∈ Z biết:
a, \(\dfrac{5}{x}=\dfrac{-10}{12}\) b, \(\dfrac{4}{-6}=\dfrac{x+3}{9}\) c, \(\dfrac{x-1}{25}=\dfrac{4}{x-1}\) d, \(\dfrac{x+1}{y}=\dfrac{-3}{5}\)
e, \(\dfrac{-12}{6}=\dfrac{x}{5}=\dfrac{-y}{3}=\dfrac{Z}{-17}=\dfrac{-t}{-9}\)
h, \(\dfrac{-24}{-6}=\dfrac{x}{3}=\dfrac{4}{y^2}=\dfrac{Z^3}{-2}\)
tìm x
\(x-\dfrac{1}{2}=\dfrac{3}{4}\)
\(x+\dfrac{7}{8}=\dfrac{3}{4}\)
\(\dfrac{1}{2}.x-\dfrac{1}{4}=\dfrac{-1}{2}\)
\(\dfrac{1}{2}-\dfrac{5}{6}:x=\dfrac{2}{3}\)
tìm x e Q
a) \(\dfrac{x+1}{3}+\dfrac{x+1}{4}+\dfrac{x+1}{5}=\dfrac{x+1}{6}\)
b) \(\dfrac{x+1}{2020}+\dfrac{x+2}{2019}=\dfrac{x+3}{2018}+\dfrac{x+4}{2017}\)
c) \(\dfrac{x+2}{327}+\dfrac{x+3}{326}+\dfrac{x+4}{325}+\dfrac{x+5}{324}+\dfrac{x+349}{5}=0\)
Tìm x biết:
1/ \(\dfrac{3}{5}-x=0,2\)
2/ \(\dfrac{x}{3}-\dfrac{1}{8}=\dfrac{5}{8}\)
3/ \(3\dfrac{1}{3}.x-6\dfrac{3}{4}=3\dfrac{1}{4}\)
Tìm \(x\) thỏa mãn:
\(\dfrac{4}{5}\)\(x\) - \(x\) - \(\dfrac{3}{2}\)\(x\) + \(\dfrac{4}{3}\) = \(\dfrac{1}{2}\) - \(\dfrac{6}{5}\)
Tìm x biết:
\(a,\dfrac{4}{5}+x=\dfrac{2}{3}\)
\(b,\dfrac{-5}{6}-x=\dfrac{2}{3}\)
\(c,\dfrac{1}{2}x+\dfrac{3}{4}=\dfrac{-3}{10}\)
\(d,\dfrac{x}{3}-\dfrac{1}{2}=\dfrac{1}{5}\)
\(e,\dfrac{x+3}{15}=\dfrac{1}{3}\)
\(h,x+30\%x=-1,3\)
\(k,3\dfrac{1}{3}x+16\dfrac{1}{4}=13,25\)
\(m,\dfrac{x-6}{2}=\dfrac{50}{x-6}\)
\(n,x-13,4=24,5-6,7.5,2\)
\(p,15,7x+3,6x=-96,5\)
\(q,2,5x-11,6=-59,1\)
Tìm x biết: a) x + \(\dfrac{2}{3}=\dfrac{4}{27}\) b) \(\dfrac{3}{4}x-\dfrac{7}{3}=\dfrac{1}{4}x+\dfrac{1}{6}\)
c) \(\dfrac{13}{10}x-\dfrac{5}{2}=\dfrac{7}{2}\) d) (3\(x\) + 2) \(\left(\dfrac{-2}{5}x-7\right)=0\)
