Question

tìm x:

a) (x-0,4).(x+1/3)=0

b) x²-x=0

Answer 1

a: =>x-0,4=0 hoặc x+1/3=0

=>x=2/5 hoặc x=-1/3

b: =>x(x-1)=0

=>x=0 hoặc x=1

Answer 2

a) \(\left(x-0,4\right)\left(x+\dfrac{1}{3}\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x-0,4=0\\x+\dfrac{1}{3}=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0,4\\x=-\dfrac{1}{3}\end{matrix}\right.\)

b) \(x^2-x=0\\ \Leftrightarrow x\left(x-1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)

Answer 3

`a)(x-0,4).(x+1/3)=0`

`@TH1:x-0,4=0=>x=0,4`

`@TH2:x+1/3=0=>x=-1/3`

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`b)x^2-x=0`

`=>x(x-1)=0`

`@TH1:x=0`

`@TH2:x-1=0=>x=1`

Answer 4

a)\(< =>\left[{}\begin{matrix}x-0,4=0\\x+\dfrac{1}{3}=0\end{matrix}\right.< =>\left[{}\begin{matrix}x=0,4\\x=\dfrac{-1}{3}\end{matrix}\right.\)

b) <=>x(x-1)=0

<=> x=0 hoăc x-1=0

<=> x=0 hoặc x=1