\(\frac{x+32}{11}+\frac{x+23}{12}=\frac{x+38}{13}+\frac{x+27}{14}\)
Tìm x
Cho \(\frac{x+32}{11}+\frac{x+23}{12}=\frac{x+38}{13}+\frac{x+27}{14}\). Tìm x.
Tìm x biết
a) x+2x+3x+4x+...+100x=-213
b)\(\frac{1}{2}x-\frac{1}{3}=\frac{1}{4}x-\frac{1}{6}\)
c)3(x-2)+2(x-1)=10
d)\(\frac{x+1}{3}=\frac{x-2}{4}\)
e)\(\frac{x-6}{7}+\frac{x-7}{8}+\frac{x-8}{9}=\frac{x-9}{10}+\frac{x-10}{11}+\frac{x-11}{12}\)
f)\(\frac{x+32}{11}+\frac{x+23}{12}=\frac{x+38}{13}+\frac{x+27}{14}\)
Tìm x biết:
\(\frac{x+32}{11}\)+ \(\frac{x+23}{12}\)= \(\frac{x+38}{13}\)+ \(\frac{x+27}{14}\)
Tìm x biết :
\(\frac{x+32}{11}\)+ \(\frac{x+23}{12}\)= \(\frac{x+38}{13}\)+ \(\frac{x+27}{14}\)
Tìm x biết
\(\frac{x+32}{11}+\frac{x+23}{12}=\frac{x+32}{13}+\frac{x+27}{14}\)
\(\frac{x+32}{11}\)+\(\frac{x+23}{12}\)=\(\frac{x+38}{13}\)+\(\frac{x+27}{14}\)
TÌM X, AI NHANH MÌNH SẼ TICK CHO!!!^-^
Tìm x:
a) 3x.(x-1) +5.(2-x) = 3x2 - 7x + 6
b) (x + 2)2 = \(\frac{1}{2}-\frac{1}{3}\)
c) \(\frac{x+32}{11}\)+ \(\frac{x+23}{12}\)= \(\frac{x+38}{13}\)+ \(\frac{x+27}{14}\)
tìm x,biết:
a)\(\frac{2}{\left(x+2\right)\left(x+4\right)}+\frac{4}{\left(x+4\right)\left(x+8\right)}+\frac{6}{\left(x+8\right)\left(x+14\right)}=\frac{x}{\left(x+2\right)\left(x+14\right)}\)
b)\(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)
c)\(\left(x+2\right)^2=\frac{38}{25}+\frac{9}{10}-\frac{11}{15}+\frac{13}{21}-\frac{15}{28}+\frac{17}{36}-...+\frac{197}{4851}-\frac{199}{4950}\)
giúp tớ với,huhu