`3^{2x-1}=243`
`->3^{2x-1}=3^{5}`
`->2x-1=5`
`->x=3`
\(3^{2x-1}=243\Leftrightarrow3^{2x-1}=3^5\Leftrightarrow2x-1=5\Leftrightarrow x=3\)
Vậy x = 3
Ta có: \(3^{2x-1}=243\)
\(\Leftrightarrow2x-1=5\)
hay x=3
\(3^{2x-1}=243\\ \Leftrightarrow3^{2x-1}=3^5\\ \Leftrightarrow2x-1=5\\ \Leftrightarrow x=3\)
32x−1=243
\(\Rightarrow\)32x−1=35
\(\Rightarrow\)2x−1=5
\(\Rightarrow\)2x=5+1
\(\Rightarrow\)2x=6
\(\Rightarrow\)x=6:2
\(\Rightarrow\)x=3
CHÚC BẠN HỌC TỐT!!!!!!