\(\left(2x-\dfrac{1}{3}\right)\left(4-5x\right)\left(7x+8\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}2x=\dfrac{1}{3}\\5x=4\\7x=-8\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{6}\\x=\dfrac{4}{5}\\x=-\dfrac{8}{7}\end{matrix}\right.\)