x.(x-\(\dfrac{2}{3}\))=0
=>x=0 hoặc x-\(\dfrac{2}{3}\)=0
=>x=0 hoặc x=\(\dfrac{2}{3}\)
Vậy x\(\in\left\{0,\dfrac{2}{3}\right\}\)
\(x.\left(x-\dfrac{2}{3}\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\x-\dfrac{2}{3}=0\Rightarrow x=0+\dfrac{2}{3}=\dfrac{2}{3}\end{matrix}\right.\)
Vậy \(x=0\) hoặc \(x=\dfrac{2}{3}\)
x . ( x - \(\dfrac{2}{3}\) ) = 0
\(\Rightarrow\) x - \(\dfrac{2}{3}\) = 0
\(\Rightarrow\) x = \(\dfrac{2}{3}\) .