Ta có (x - 5 ). (x + 3 ) > 0
⇔ \(\left[{}\begin{matrix}\left\{{}\begin{matrix}x-5>0\\x+3>0\end{matrix}\right.\\\left\{{}\begin{matrix}x-5< 0\\x+3< 0\end{matrix}\right.\end{matrix}\right.\)
⇔\(\left[{}\begin{matrix}\left\{{}\begin{matrix}x>5\\x>-3\end{matrix}\right.\\\left\{{}\begin{matrix}x< 5\\x< -3\end{matrix}\right.\end{matrix}\right.\)
⇔ \(\left[{}\begin{matrix}x>5\\x< -3\end{matrix}\right.\)
Vậy x > 5 hoặc x < - 3
Học tốt
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tìm x biết :
\(\left|x-1\right|+2.\left|x-2\right|+3.\left|x-3\right|+4.\left|x-4\right|+5.\left|x-5\right|+20x=0\)
Tìm x,y biết :
1 ) | 4 - x | + | 2y +1 | = 0
2) | x - 3 | = | 5 - 2x |
Tìm x , biết \(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}+\frac{x+349}{5}=0\)
giúp mk vs
Tìm x biết:
a) x^2-3.x=0
b) 2.x^2+5.x=0
c) x^2+1=0
d) x^2-1=0
e) x.(x-3)-x+3=0
g) x^2.(x+2)-9.x-18=0
Tìm x biết :
\(\left(x^2-20\right)\left(x^2-15\right)\left(x^2-10\right)\left(x^2-5\right)< 0\)
Tìm x biết :
a) | 2x - 1 | = 4
b) -3 | 2x | + | 5 - x | = 1
c) 2^x + 3 = 2^x - 1 = 15/64
d) | -3 + 5 | = x
e) ( x - 1 )^100 + ( x - y )^98 = 0
f) ( x - 7 )^x + 1 - ( x - 7 )^x + 5 = 0
Bài 1:tìm x, biết
A)(x-1)×(x+2)<0
B) (2x-3)×(x-5)>hoặc =0
C ) (x-1/3)×(x+2/5)< hoặc =0
D) (x+3/2)×(1-x) >0
tìm x thuộc Z biết
-12(x - 5) + 7(3 - x) = 5
(x - 2).(x + 4) = 0
Tìm x biết:
a. (x - 2).(x + 3/4) > 0
b. (2x - 5).(1 - 3x) > 0
c. (3 - 2x).(x + 1) < 0
d.(5x + 11).(7 - x) < 0
