\(\frac{x-1}{x+2}=\frac{x-2}{x+3}\Leftrightarrow\frac{x+2-3}{x+2}=\frac{x+3-5}{x+3}\Leftrightarrow\)
\(\Leftrightarrow\frac{x+2}{x+2}+\frac{-3}{x+2}=\frac{x+3}{x+3}+\frac{-5}{x+3}\)
\(\Leftrightarrow1+\frac{-3}{x+2}=1+\frac{-5}{x+3}\Leftrightarrow\frac{-3}{x+2}=\frac{-5}{x+3}\Leftrightarrow\)
<=> -3(x+3) = -5(x+2)
<=> - 3x -9 = -5x-10
<=> -3x +5x = -10+9
<=> 2x = -1
<=> x = -1/2