Các câu hỏi tương tự
Tìm x biết:a) \(-\frac{2}{3}\left(x-\frac{1}{4}\right)=\frac{1}{3}\left(2x-1\right)\)
b)\(\frac{1}{5}.2^x+\frac{1}{3}.2^x^{+1}=\frac{1}{5}.2^7+\frac{1}{3}2^8\)
Bài 4. Tìm x ∈ N biết:
a) x3 = 27 b) (2x – 1)3 = 8
c) (2x – 3)2 = 9 d) 2x + 5= 3^4 : 3^2
3^4 tức là 3 mũ 4
Tìm x
\(\frac{7}{9}:\left(2+\frac{3}{4}X\right)+\frac{5}{9}=\frac{23}{27}\)
bài 1 tính bằng cách hợp lí nếu có thểfrac{-5}{12}-frac{-3}{24}b) 5frac{5}{13}-(1frac{1}{2}+3frac{5}{13})c)frac{-13}{37}.frac{5}{23}+frac{-13}{37}.frac{18}{23}+frac{50}{37}d)(0,5 -frac{3}{2}):1frac{1}{6}+75%bài 2 tìm x biết-7/5 +x -3/4-7/4 + 1/4 : x 3/2
Đọc tiếp
bài 1 tính bằng cách hợp lí nếu có thể
\(\frac{-5}{12}\)-\(\frac{-3}{24}\)=
b) 5\(\frac{5}{13}\)-(1\(\frac{1}{2}+3\frac{5}{13}\))
c)\(\frac{-13}{37}.\frac{5}{23}+\frac{-13}{37}.\frac{18}{23}+\frac{50}{37}\)
d)(0,5 -\(\frac{3}{2}\)):1\(\frac{1}{6}+75\%\)
bài 2 tìm x biết
-7/5 +x = -3/4
-7/4 + 1/4 : x = 3/2
Tìm x biết :
a)\(\frac{2}{3}x-50\%x-\left(-\frac{4}{5}\right):1\frac{3}{5}=-0,12\)\(+1\frac{3}{25}\)
b)\(\left(-1\frac{1}{6}+\frac{2}{3}-\frac{3}{4}\right):x+\left(-1\frac{11}{12}\right).1\frac{21}{23}=-6\frac{1}{3}\)
c)\(50\%x-\frac{1}{3}x-\left(\frac{-2}{3}\right)^2.\left(-1\frac{1}{8}\right)=-119\frac{3}{4}+120\frac{5}{6}\)
\(\frac{-9}{46}-4\frac{1}{23}:\left(3\frac{1}{4}-x:\frac{3}{5}\right)+2\frac{8}{23}=1\)
\(\frac{7}{9}:\left(2+\frac{3}{4}x\right)+\frac{5}{9}=\frac{23}{27}\)
giúp mình tìm x với
Tìm x biết :
\(\left[\frac{6:\frac{3}{5}-1\frac{1}{16}.\frac{6}{7}}{4\frac{1}{5}.\frac{10}{11}+5\frac{2}{11}}-\frac{\left(\frac{3}{20}+\frac{1}{2}-\frac{1}{15}\right).\frac{12}{49}}{3\frac{1}{3}+\frac{2}{9}}\right].x=2\frac{23}{96}\)
Rút gọn:
A=\(\frac{2-\frac{2}{19}+\frac{2}{23}-\frac{1}{1010}}{3-\frac{3}{19}+\frac{3}{23}-\frac{3}{2020}}\)\(.\frac{4-\frac{4}{29}+\frac{4}{41}-\frac{1}{505}}{5-\frac{5}{29}+\frac{5}{41}-\frac{1}{404}}\)