Question

tìm x , biết:

(4x - 5)² - 8x + 10 = 0 

mik đag cần gấp 
mọi người giúp mik nha 

Answer 1

`(4x-5)^2 - 2(4x-5) = 0`

`-> (4x-5)(4x-7) = 0`

`->` \(\left[{}\begin{matrix}4x-5=0\\4x-7=0\end{matrix}\right.\)

`->` \(\left[{}\begin{matrix}x=\dfrac{5}{4}\\x=\dfrac{7}{4}\end{matrix}\right.\)

Answer 2

\(\left(4x-5\right)^2-2\left(4x-5\right)=0\\ \left(4x-5\right)\left(4x-5-2\right)=0\\ \left(4x-5\right)\left(4x-9\right)=0\\ \left[{}\begin{matrix}4x-5=0\\4x-7=0\end{matrix}\right.=>\left[{}\begin{matrix}x=\dfrac{5}{4}\\x=\dfrac{7}{4}\end{matrix}\right.\)