2x+2x+1+2x+2+.....+2x+2020 = 22021 - 1
2x.(1+2+22+....+22020) = 2021 - 1
Đặt M = 1+2+22+...+22020
2M = 2+22+23+...+22021
2M - M = 22021-1
=> M = 22021 - 1
Thay vào, ta có:
2x.(22021 - 1) = 22021 - 1
=> 2x = 1
=> x = 0
2x+2x+1+2x+2+.....+2x+2020 = 22021 - 1
2x.(1+2+22+....+22020) = 2021 - 1
Đặt M = 1+2+22+...+22020
2M = 2+22+23+...+22021
2M - M = 22021-1
=> M = 22021 - 1
Thay vào, ta có:
2x.(22021 - 1) = 22021 - 1
=> 2x = 1
=> x = 0
Tìm x:
x-1/2020+x-2/2021=x+1/2018+x+2/2017
Nếu 1/3 + 1/6 +1/10 + ...... + 1/x.(x+1) : 2 = 2019/2021
A.x = 2019/2020 B. x = 2019 C. x = 2020 D. x = 2021
\(\dfrac{x+1}{2021}\) + \(\dfrac{x+2}{2020}\) + \(\dfrac{x+1}{2019}\) = -3
x-4/2022+x-3/2021+x-2/2020+x-1/2019=-4
Cho x1 + x2 + x3 + ... + x2021 = 0 và x1 + x2 = x3 + x4 = ... = x2019 + x2020 = 2. Tìm x2021.
(x+1/2)mũ 2021+2020+2021
1/1.3+2/3.5+2/5.7+....+2/x.(x+2)=2020/2021 giúp mình với
1/1.3+2/3.5+2/5.7+....+2/x.(x+2)=2020/2021 giúp mình với
Tìm x bt:
\(\dfrac{x+1}{2021}+\dfrac{x+2}{2020}+\dfrac{x+3}{2019}\)