=>1/6(2x+2)=5/6-2/3=1/6
=>2x+2=1
hay x=-1/2
2/3 + 1/6 . (2x + 2 ) = 5/6
=> 1/6 (2x + 2 ) = 5/6 - 2/3 = 1/6
=> 2x + 2 = 1
hay x = - 1/2
\(2,x\) là sao :vvvv
\(\dfrac{2}{3}+\dfrac{1}{6}\cdot\left(2x+2\right)=\dfrac{5}{6}\)
\(\dfrac{1}{6}\cdot\left(2x+2\right)=\dfrac{5}{6}-\dfrac{2}{3}\)
\(\dfrac{1}{6}\cdot\left(2x+2\right)=\dfrac{5}{6}-\dfrac{4}{6}=\dfrac{1}{6}\)
\(2x+2=\dfrac{1}{6}:\dfrac{1}{6}\)
\(2x+2=1\)
\(2x=1-2\)
\(2x=-1\)
\(x=\left(-1\right):2\)
`=>x=-1/2`