Question

Tìm x ,biết:

\(2-\left(\frac{37}{7}+x-3\right)\times\frac{49}{11}=0\)

Answer 1

\(2-\left(\frac{37}{7}+x-3\right)x\frac{49}{11}=0\)

\(\left(\frac{37}{7}+x-3\right)x\frac{49}{11}=2\)

\(\frac{37}{7}+x-3=\frac{22}{49}\)

\(x=-\frac{90}{49}\)

Answer 2

\(2-\left(\frac{37}{7}+x-3\right)\cdot\frac{49}{11}=0\)

\(\left(\frac{37}{7}+x-3\right)\cdot\frac{49}{11}=0+2\)

\(\left(\frac{37}{7}+x-3\right)\cdot\frac{49}{11}=2\)

\(\frac{37}{7}+x-3=2:\frac{49}{11}\)

\(\frac{37}{7}+x-3=\frac{22}{49}\)

\(\frac{37}{7}+x=\frac{22}{49}+3\)

\(\frac{37}{7}+x=\frac{169}{49}\)

\(x=\frac{169}{49}-\frac{37}{7}\)

\(x=-\frac{90}{49}\)