Question

Tìm x, biết

( x+\(\dfrac{1}{2}\)).( 2x+\(\dfrac{1}{7}\) )-3\(\dfrac{1}{7}\)(x+50%)=0

Answer 1

Do (x + \(\dfrac{1}{2}\))(2x + \(\dfrac{1}{7}\)) - 3\(\dfrac{1}{7}\left(x+50\%\right)=0\)

<=> (x + \(\dfrac{1}{2}\))(2x + \(\dfrac{1}{7}\)) = 3\(\dfrac{1}{7}\left(x+50\%\right)\)

<=> 2x(x + \(\dfrac{1}{2}\)) + \(\dfrac{1}{7}\left(x+\dfrac{1}{2}\right)\) = \(\dfrac{22}{7}x+\dfrac{11}{7}\)

<=> 2x² + x + \(\dfrac{1}{7}x+\dfrac{1}{14}=\dfrac{22}{7}x+\dfrac{11}{7}\)

<=> \(\dfrac{22}{7}x^2-\dfrac{22}{7}x=\dfrac{11}{7}-\dfrac{1}{14}\)

<=> \(\dfrac{22}{7}x=\dfrac{3}{2}\)

<=> x = \(\dfrac{21}{44}\)

@Trần Nguyệt Hà