Với x>0
\(\Rightarrow x+2016+x+2017+2018=3x\)
\(\Rightarrow x=2016+2017+2018\)
\(\Rightarrow x=6051\)(t/m)
Với x<0
\(\Rightarrow2016-x+2017-x+2018=3x\)
\(\Rightarrow6051-2x=3x\)
\(\Rightarrow x=\frac{6051}{5}\)(loại)
| x+2016 | + | x+2017 |+2018=3x
\(\Rightarrow\)x + 2016 + x + 2017 = 2018
\(\Rightarrow\)x2 + 2016 + 2017 + 2018 = 3x
\(\Rightarrow\)x2 + 6051 = 3x
\(\Rightarrow\)3x - 2x = 6051
\(\Rightarrow\)1x =6051
\(\Rightarrow\)x = 6051