a) \(\left(x-5\right)\left(2x+1\right)>0\)
<=> \(\hept{\begin{cases}x-5>0\\2x+1>0\end{cases}}\)hoặc \(\hept{\begin{cases}x-5< 0\\2x+1< 0\end{cases}}\)
<=>\(\hept{\begin{cases}x>5\\x>\frac{-1}{2}\end{cases}}\)hoặc \(\hept{\begin{cases}x< 5\\x< \frac{-1}{2}\end{cases}}\)
<=>\(\orbr{\begin{cases}x>5\\x< \frac{-1}{2}\end{cases}}\)