\(a)\) \(\frac{x+1}{2x+1}=\frac{0,5x+2}{x+3}\)
\(\Leftrightarrow\)\(\left(2x+1\right)\left(0,5x+2\right)=\left(x+1\right)\left(x+3\right)\)
\(\Leftrightarrow\)\(2x\left(0,5x+2\right)+0,5x+2=x\left(x+1\right)+3\left(x+1\right)\)
\(\Leftrightarrow\)\(x^2+4x+0,5+2=x^2+x+3x+3\)
\(\Leftrightarrow\)\(x^2+4x-x^2-4x=3-0,5-2\)
\(\Leftrightarrow\)\(0=0,5\) ( vô lí :'< )
Vậy không có x thoả mãn đề bài
Tìm x , biết :
a\(\frac{x+1}{2x+1}=\frac{0,5x+2}{x+3}\)
Tìm x biết \(\frac{x+1}{2x+1}=\frac{0,5x+2}{x+3}\)
Tìm x biết:
\(\frac{x^2}{6}=\frac{24}{25}\)\(\frac{x+1}{2x+1}=\frac{0,5x+2}{x+3}\)Tìm x biết :
a, \(\left|0,5x-2\right|-\left|x+\frac{1}{3}\right|=0\)
b, \(2x-\left|x+1\right|=\frac{1}{2}\)
c, \(\left|2x-1\right|-\left|x+\frac{1}{3}\right|=0\)
d, \(3x-\left|x+15\right|=\frac{5}{4}\)
tim x biet
a;\(\frac{3x+2}{5x+7}=\frac{3x-1}{5x+1}\)
b; \(\frac{x+1}{2x+1}=\frac{0,5x+2}{x+3}\)
Tìm x
|10x +7 | < 37
|3 - 8x | nhỏ hơn hoặc bằng 19
| x +3| - 2x = | x- 4 |
\(\frac{3x+2}{5x+7}\)=\(\frac{3x-1}{5x+1}\)
\(\frac{x+1}{2x+1}\)=\(\frac{0,5x\cdot2}{x+3}\)
Tìm x :
\(\frac{x+1}{2x+1}=\frac{0,5x-2}{x-3}\)
Không tick không làm người :)
Tìm x
a, \(-\frac{22}{15}x+\frac{1}{3}=\text{|}-\frac{2}{3}+\frac{1}{5}\text{|}\)
b,\(x:15=8:24\)
c,\(\frac{-3x+2}{5x+7}=\frac{3x-1}{5x+1}\)
d, \(\frac{x+1}{2x+1}=\frac{0,5x+2}{x+3}\)
nói cách làm lun nha
1\(|0,5x|=0,5x\)
2\(|\frac{1}{3}x|=\frac{1}{3}x\)
3\(|-\frac{2}{3}|=\frac{2}{3}x\)
4\(|-\frac{1}{5}|=\frac{1}{5}x\)
