\(3^x+4^2=19^6\div\left(19^3.19^2\right)-3.1^{2021}\)
\(3^x+4^2=19^6\div\left(19^5\right)-3.1\)
\(3^x+4^2=19-3\)
\(3^x+16=16\)
\(3^x=0\)
\(x=0\)
\(3^x+4^2=19^6:\left(19^3.19^2\right)-3.1^{2021}\)
\(3^x+4^2=19^6:19^5-3.1\)
\(3^x+4^2=19-3\)
\(3^x+16=16\)
\(3^x=16-16\)
\(3^x=0\)
......................