b, (x - 1)(x - 2)= 0
Suy ra , ta có 2 trường hợp
Th1:(x -1)(x - 2)=0
Suy ra (x-1)=0 suy ra x=1
Th2:(x -1)(x - 2)=0
Suy ra (x -2)=0 suy ra x =2
Vậy x thuộc {1;2}
TÍCH NHÉ BẠN
tìm x biết :
a,(2x+ 4/5) (3x-1/2)= 0
b,(x-2/5) (x+4/7)= 0
c,-1 =|x- 5/6|= 1/2
d,x+ 5/8 x- 12/16x= 1
Tìm x biết :
a) 1+3+5+7+...+(2x-1) = 225
b) x+(x+1)+(x+2)+...+(x+2010) = 2029099
c) 2+4+6+8+...+2x=210
bài 1 tìm x
a. 5 - 3(x+4) = -1
b.(x-1) - (x+2) = 0
c.( \(\dfrac{1}{2}\) + x )-( \(\dfrac{1}{3}\) - x) = 0
d. 2x2 - 3 = 5
e. x(2x -1) = 0
g. \(\dfrac{1}{3}\) . x2 - \(\dfrac{1}{6}\)=\(\dfrac{7}{6}\)
a) \(\dfrac{12}{16}\) = \(\dfrac{-x}{4}\) = \(\dfrac{21}{y}\) = \(\dfrac{z}{80}\)
b) \(\dfrac{1}{3}\) x + \(\dfrac{2}{5}\) ( x - 1 ) = 0
c) ( 2x - 3 )( 6 - 2x ) = 0
d) \(\dfrac{-2}{3}\) - \(\dfrac{1}{3}\) ( 2x - 5 ) = \(\dfrac{3}{2}\)
e) 2 |\(\dfrac{1}{2}\) x - \(\dfrac{1}{3}\) | - \(\dfrac{1}{4}\)
Tìm x:
a) 2+4+6+...+2x= 210
b) 1+3+5+...+ (2x-1) = 225
Tìm x biết
a) 1+3+5+...+ (2x-1)= 225
b) 2+4+6+...+ 2x= 210
Tìm x biết :
a) (x + 10) . (2y - 5) = 143 ( Riêng câu này tìm cả y nữa nhé)
b) x + (x + 1) + (x + 2) +...+ (x+30) = 1240
c) 1 + 2 + 3 +...+ x =210
d) 2 + 4 + 6 +...+ 2x =210
e) 1 + 3 + 5 + ... + (2x - 1) = 225
Ai giúp mình sẽ được 10 tick.
1/Tìm x ,y biết
a/(x-1)*(x-2)=-5
2/ tìm x biết
a/2*(x-1)-3*(x-2)=-5-2*(x-3)
b/x*(x-2) < 0c
c/(x-3)*(2x+6)*(3x-15)=0
