Question

Tìm x:

a, 5^(x+2)(x+3)=1

b, (x-4)¹⁰⁰+|3-y|=0

Answer 1

a)

vì 5^(x+2)(x+3)=1

=> 5^(x+2)(x+3)=5⁰

=> (x+2)(x+3)=0

\(\Rightarrow\left[{}\begin{matrix}x+2=0\Rightarrow x=-2\\x+3=0\Rightarrow x=-3\end{matrix}\right.\)

vậy \(x\in\left\{-2;-3\right\}\)

b)

ta có \(\left\{{}\begin{matrix}\left(x-4\right)^{100}\ge0\forall x\\\left|3-y\right|\ge0\forall y\end{matrix}\right.\)

mà (x-4)¹⁰⁰+|3-y|=0

\(\Rightarrow\left\{{}\begin{matrix}x-4=0\Rightarrow x=4\\3-y=0\Rightarrow y=3\end{matrix}\right.\)

vậy (x;y) = (4;3)