2/3 x + 1/3 (x - 1) = 1/4
2/3 x + 1/3 x - 1/3 = 1/4
x - 1/3 = 1/4
x = 1/4 + 1/3
x = 7/12
\(\dfrac{2}{3}x+\dfrac{1}{3}\left(x-1\right)=\dfrac{1}{4}\\ \Leftrightarrow\dfrac{2}{3}x+\dfrac{1}{3}x-\dfrac{1}{3}=\dfrac{1}{4}\\ \Leftrightarrow\left(\dfrac{2}{3}+\dfrac{1}{3}\right)x=\dfrac{1}{4}+\dfrac{1}{3}\\ \Leftrightarrow\dfrac{3}{3}x=\dfrac{1.3+1.4}{12}\\ \Leftrightarrow x=\dfrac{7}{12}\)
Vậy \(x=\dfrac{7}{12}\)