Question

tim x (5-2x)^2-16=0 mn giup e vs ak <3

Answer 1

\(\left(5-2x\right)^2-16=0\)

\(\Leftrightarrow\left(5-2x\right)^2-4^2=0\)

\(\Rightarrow\left(5-2x-4\right)\left(5-2x+4\right)=0\)

\(\Rightarrow\orbr{\begin{cases}5-2x-4=0\\5-2x+4=0\end{cases}\Leftrightarrow\orbr{\begin{cases}-2x=4-5\\-2x=-4-5\end{cases}}\Leftrightarrow\orbr{\begin{cases}-2x=-1\\-2x=-9\end{cases}}}\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{-1}{-2}=\frac{1}{2}\\x=\frac{-9}{-2}=\frac{9}{2}\end{cases}}\)

Vậy ................................

Answer 2

= 5^2 - 2.5.2x + (2x)\(^2\)- 16 = 0

=> x = 4,5

Answer 3

Cam on ban nhieu nha <3