\(\frac{2^{7x}}{2^{3x}}=64\)
\(\Rightarrow\frac{\left(2^7\right)^x}{\left(2^3\right)^x}=2^6\)
\(\Rightarrow\left(\frac{128}{8}\right)^x=2^6\)
\(\Rightarrow16^x=2^6\)
\(\Rightarrow2^{4x}=2^6\)
\(\Rightarrow4x=6\)
\(\Rightarrow x=\frac{6}{4}=\frac{3}{2}\)
Ta co 27x / 23x = 64
===> 27x-3x = 64
===> 24x = 64 = 26
=====> 4x = 6
===> x = 1,5