a.20-[7(x-3)+4]=2
[7(x-3)+4]=18
7(x-3)=18-4
7(x-3)=14
x-3=2
x=5
Vậy x=5
b.4x3+12=120
4x3=200-12
4x3=188
x3=188:4
x3=47
\(\Rightarrow x\in\notin\)
c.3 . 2x-3=45
2x-3=45:3
2x-3=15
2x=15+3
2x=18
\(\Rightarrow x\in\notin\)
a, bằng \(\frac{39}{7}\)
b, bằng 3
c,bằng 4
a) 20 - [7(x - 3) + 4] = 2
7(x - 3) + 4 = 20 - 2
7(x - 3) + 4 = 18
7(x - 3) = 18 - 4
7(x - 3) = 14
x - 3 = 14 : 7
x - 3 = 2
x = 2 + 3
x = 5