\(\frac{2}{3}+\frac{8}{35}< \frac{x}{105}< \frac{1}{7}+\frac{2}{5}\)\(+\frac{1}{3}\)
\(\frac{94}{105}< \frac{x}{105}< \frac{92}{105}\)
\(\Rightarrow94< x< 92\)
\(\Rightarrow x=93\)
Vậy x=93
\(\frac{2}{3}+\frac{8}{35}< \frac{x}{105}< \frac{1}{7}+\frac{2}{5}+\frac{1}{3}\)
\(\frac{2.35+8.3}{105}< \frac{x}{105}< \frac{15+42+35}{105}\)
\(94< x< 92\)
Vậy ko có x thỏa mãn
\(\frac{2}{3}+\frac{8}{35}< \frac{x}{105}< \frac{1}{7}+\frac{2}{5}+\frac{1}{3}\)
\(\Rightarrow\frac{94}{105}< \frac{x}{105}< \frac{92}{105}\)
\(\Rightarrow94< x< 92\)
\(\Rightarrow x\in\varnothing\)
\(Tacó:\frac{2}{3}+\frac{8}{35}< \frac{x}{105}< \frac{1}{7}+\frac{2}{5}+\frac{1}{3}\)
\(\frac{70}{105}+\frac{24}{105}< \frac{x}{105}< \frac{15}{105}+\frac{42}{105}+\frac{35}{105}\)
\(\frac{94}{105}< \frac{x}{105}< \frac{92}{105}\)
\(Suyra:94< x< 92\)
Suy ra không có giá trị nào của x thỏa mãn.
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