Question

Tìm số nguyên n:

 

 

a) (n+5) chia hết cho (n-2)

b) (2n+1) chia hết cho (n-5)

c)n²+3n-13 chia hết cho n+3

 

Answer 1

n²+3n-13 chia hết cho n+3

=> n.(n+3)-13 chia hết cho n+3

Vì n.(n+3) chia hết cho n+3

=> -13 chia hết cho n+3

=> n+3 thuộc Ư(-13)

n+3	n
1	-2
-1	-4
13	10
-13	-16

KL: n thuộc........................

Answer 2

2n+1 chia hết cho n-5

=> 2n-10+11 chia hết cho n-5

Vì 2n-10 chia hết cho n-5

=> 11 chia hết cho n-5

=> n-5 thuộc Ư(11)

n-5	n
1	6
-1	4
11	16
-11	-6

KL: n thuộc................................

Answer 3

a) n+5 chia hết cho n-2=>(n-2)+7 chia hết cho n-2

=>7 chia hết cho n-2

=>n-2=Ư(7)=(-1,-7,1,7)

=>n=(1,-5,3,9)

Vậy n=1,-5,3,9

b) 2n+1 chia hết cho n-5=>2n-10+11=2.(n-5)+11 chia hết cho n-5

=>11 chia hết cho n-5

=>n-5=Ư(11)=(-1,-11,1,11)

=>n=(4,-6,6,16)

Vậy n=4,-6,6,16

c) n²+3n-13 chia hết cho n+3=>n.(n+3)-13 chia hết cho n+3

=>13 chia hết cho n+3

=>n+3=Ư(13)=(-1,-13,1,13)

=>n=(-4,-16,-2,10)

Vậy n=-4,-16,-2,10

Answer 4

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Answer 5

cac ban gioi qua vay 

Answer 6

Hồ Thu Giang ơi, mình thấy cách làm của cậu cũng đúng nhưng mình cần làm ngắn gọn hơn nữa.

Answer 7

Minhf đồng ý với cÂU TRẢ LỜI CỦA hoàng thu hương.

Answer 8

minh dong y voi cau tra loi cua LE CHI CUONG

Answer 9

Mnk dong y voi y kien cua cau

Answer 10

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Answer 11

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Answer 12

mik o hiểu

Answer 13

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                                                                         THE END