Question

Tìm \(n\);biết:

\(\dfrac{1}{8}.16^n=2^n\)

Answer 1

\(\dfrac{1}{8}.16^n=2^n\Leftrightarrow16^n=2^n.8\)

\(2^{4n}=2^{n+3}\Rightarrow4n=n+3\Rightarrow3n=3\Rightarrow n=\dfrac{3}{3}=1\)

Answer 2

\(\dfrac{1}{8}.16^n=2^n\)

\(\Rightarrow\dfrac{16^n}{8}=2^n=\dfrac{24^n}{2^3}=2^n\)

\(\Rightarrow2^{4^n}-3=2^n\)

\(\Rightarrow4^n-3=n\)

\(\Rightarrow n=1\)

Vậy \(n=1\)

Answer 3

1/8.16^n=2^n

1/8.2^4n=2^n

1/2^3=2^n:2^4n

2^-3=2^n-4n

2^ -3=2^-3n

Suy ra n=1

Answer 4

tao chiu