a) 32 < 2^n < 128
<=>2^5 < 2^n <2^7
<=>5<n<7
Vậy n=6
a) 32 < 2^n < 128
<=>2^5 < 2^n <2^7
<=>5<n<7
Vậy n=6
cho phuong trinh x2+(2m-5)x-n=0 cho m=5 tim n nguyen nho nhat de bphuong trinh co nghiem duong
tim m,n nguyen duong de
9^m-3^m=n^4+2n^3+n^2+2n
tim nghiem nguyen duong cua pt 2^m!+6^n=10^n
Tim n de A nguyen : (n+7)/(2n-3)
tim cac so nguyen n de n^3 - 3n^2 - 3n -1 chia het n^2 + n +1
tim so tu nhien n de 5^(2n^2-6n+2) -12 la so nguyen to
B1. Cho f(1)=1008,f(1)+f(2)+...+f(n)=n^2.f(n) f(n)la ham so duong
tinh f(2015)
B2 Cho cac so nguyen to q,p,r,s sao cho cac so sau deu la so nguyen to p^s+s^q,q^s+s^r,r^s+s^p
tim cac so p,q,r,s
B3 co a,b,c duong a mu 3+bmu3=c^3
so sanh a^2015+b^2015 va c^2015
B1. Cho f(1)=1008,f(1)+f(2)+...+f(n)=n^2.f(n) f(n)la ham so duong
tinh f(2015)
B2 Cho cac so nguyen to q,p,r,s sao cho cac so sau deu la so nguyen to p^s+s^q,q^s+s^r,r^s+s^p
tim cac so p,q,r,s
B3 co a,b,c duong a mu 3+bmu3=c^3
so sanh a^2015+b^2015 va c^2015
tim x nguyen duong de 4x^3+14x^2+9x-6 la so chinh phuong