Ta có:
\(P=\frac{\left(x^2+1\right)^2+1}{x^2+1}\)
\(P=\left(x^2+1\right)+\frac{1}{x^2+1}\)
Dễ thấy x2 + 1 > 0
Áp dụng BĐT Cauchy - Schwarz với hai số thực không âm ta có:
\(P=\left(x^2+1\right)+\frac{1}{x^2+1}\ge2\sqrt{\left(x^2+1\right).\frac{1}{x^2+1}}=2\)
Dấu "=" xảy ra khi và chỉ khi x2 + 1 = \(\frac{1}{x^2+1}\) \(\Leftrightarrow\) x = 0
Vậy Pmin = 2 \(\Leftrightarrow\) x = 0
1. gpt : \(\frac{2x+1}{\sqrt{x^2+2}}+\left(x+1\right)\sqrt{1+\frac{2x+1}{x^2+2}}+x=0\)
2. \(\left\{{}\begin{matrix}x,y,z>0\\x+y+z\le\frac{3}{2}\end{matrix}\right.\) Tìm min \(Q=\frac{x}{y^2z}+\frac{y}{z^2x}+\frac{z}{x^2y}+\frac{x^5}{y}+\frac{y^5}{z}+\frac{z^5}{x}\)
tìm min của \(A=2x^2-y^2+x+\frac{1}{x}+1\)
\(\left\{{}\begin{matrix}x,y,z>1\\x+y+z\le6\end{matrix}\right.\). Tìm min \(P=\frac{x}{y^2-2y+1}+\frac{y}{z^2-2z+1}+\frac{z}{x^2-2x+1}\)
1. a) Tìm \(n\in N\)*, \(n>2008\) sao cho \(2^{2008}+2^{2012}+2^{2013}+2^{2014}+2^{2016}+2^n\) là số chính phương
b) tìm x,y > 0 thỏa mãn \(x^2+y^2=2\left(x+y\right)\left(\sqrt{x}+\sqrt{y}-2\right)\)
2. a) \(\left\{{}\begin{matrix}a\ge0\\a+b\ge1\end{matrix}\right.\). Min \(A=\frac{8a^2+b}{4a}+b^2\)
b) \(\left\{{}\begin{matrix}a,b\ge0\\\left(a-b\right)^2=a+b+2\end{matrix}\right.\). Cmr: \(\left(1+\frac{a^3}{\left(b+1\right)^3}\right)\left(1+\frac{b^3}{\left(b+1\right)^3}\right)\le9\)
c) \(x,y>0;\left(x+\sqrt{1+x^2}\right)\left(y+\sqrt{1+y^2}\right)=2020\). Min P = x + y
d) \(x,y,z>0;\sqrt{x^2+y^2}+\sqrt{y^2+z^2}+\sqrt{z^2+x^2}=6\). Min \(P=\frac{x^2}{y+z}+\frac{y^2}{z+x}+\frac{z^2}{x+y}\)
e) \(\left\{{}\begin{matrix}x,y,z>0\\x+y+z+4xyz=4\end{matrix}\right.\) Cmr: \(\left(1+xy+\frac{y}{z}\right)\left(1+yz+\frac{z}{x}\right)\left(1+zx+\frac{x}{y}\right)\ge27\)
f) \(\left\{{}\begin{matrix}x,y,z\ge1\\3x^2+4y^2+5z^2=52\end{matrix}\right.\). Min P = x + y + z
g) \(x,y>0\). Min \(P=\frac{2}{\sqrt{\left(2x+y\right)^3+1}-1}+\frac{2}{\sqrt{\left(x+2y\right)^3+1}-1}+\frac{\left(2x+y\right)\left(x+2y\right)}{4}-\frac{8}{3\left(x+y\right)}\)
Tìm Min của\(\left(1-\frac{1}{x^2}\right)\left(1-\frac{1}{y^2}\right)\)
Biết X+Y=1
cho x,y>0 thỏa mãn x+y=1 Tìm MIN A=2x2-y2+x+\(\frac{1}{x}+2020\)
Cho x,y>0 và 2x+3y \(\le\) 2.Tìm min của \(A=\frac{4}{4x^2+9y^2}+\frac{9}{xy}\)
1. tìm max, min : a) \(B=\frac{x-y}{x^4+y^4+6}\)
b) \(C=\frac{2x+3y}{2x+y+3}\) với \(4x^2+y^2=1\)
c) \(P=\frac{x+y}{x^2-xy+y^2}\) với \(1\le x,y\le2\)
2. Cho biểu thức \(A=\frac{a^3+b^3+c^3}{abc}\) với \(1\le a\le b\le c\le2\)
a) Cmr: \(A\le\frac{b}{c}+\frac{c}{b}+\frac{a}{c}+\frac{c}{a}\) b) Tìm Max A
\(3\sqrt{x^2-\frac{1}{4}+\sqrt{x^2+x+\frac{1}{4}}}=\frac{1}{2}\left(2x^3+x^2+2x+1\right)\)
