Lời giải:
a) ĐKXĐ: \(x^2-x+1>0\)
\(\Leftrightarrow (x-\frac{1}{2})^2+\frac{3}{4}>0\)
\(\Leftrightarrow x\in\mathbb{R}\)
b)
ĐKXĐ: \(\left\{\begin{matrix} x-\sqrt{2x-1}>0\\ 2x-1\geq 0\end{matrix}\right.\Leftrightarrow \left\{\begin{matrix} \frac{(2x-1)-2\sqrt{2x-1}+1}{2}>0\\ 2x-1\geq 0\end{matrix}\right.\)
\(\Leftrightarrow \left\{\begin{matrix} \frac{(\sqrt{2x-1}-1)^2}{2}>0\\ 2x-1\geq 0\end{matrix}\right.\Leftrightarrow \left\{\begin{matrix} \sqrt{2x-1}\neq 1\\ 2x-1\geq 0\end{matrix}\right.\)
\(\Leftrightarrow \left\{\begin{matrix} x\neq 1\\ x\geq \frac{1}{2}\end{matrix}\right.\)