Ta có : 17 = 17
46 = 2 . 23
220 = 22 . 5 . 11
=> BCNN ( 17,46,220 ) = 22 . 5 . 11 . 17. 23 = 86020
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Ta có : 17 = 17
46 = 2 . 23
220 = 22 . 5 . 11
=> BCNN ( 17,46,220 ) = 22 . 5 . 11 . 17. 23 = 86020
tim BCNN (8,12)
BCNN(5,7,8)
BCNN(12,16,48)
Biet rang : BCNN(a,b).UCLN(a,b)
a, BCNN cua hai so la 600, UCLN cua chung nho hon 10 lan BCNN. So thu 1 la 120, tim so thu 2.
b, UCLN cua hai so la 12, BCNN cua chung lon gap 6 lan UCLN . So t 1 la 24, tim so t 2
c, Tong cua hai so bang 60, tong giua UCLN va BCNN cua chung la 84. Tim hai so do.
Tim BCNN(12,16)
tim BCNN 12,64
tim UCLN (56,140)va BCNN (56,140)
tim BC (56.140)
UC (56,140)
Tim BCNN(22;24;32)
22=
24=
32=
BCNN(22;24;32)=…....
Ok
tim BCNN cua 34;68
tim BCNN cua (16;34;240)
tim BCNN (56,140)