BCNN ( 8,12,15 ) = 23.3.5 = 120
ta có : 8 = 23
12 = 22.3
15 = 3.5
8=23
12=22.3
15=3.5
BCNN(8;12;15)=23.3.5=120
Ta có: 8 = 23
12 = 22.3
15 = 3.5
=> BCNN(8, 12, 15) = 23.3.5 = 120
BCNN ( 8,12,15 ) = 23.3.5 = 120
ta có : 8 = 23
12 = 22.3
15 = 3.5
8=23
12=22.3
15=3.5
BCNN(8;12;15)=23.3.5=120
Ta có: 8 = 23
12 = 22.3
15 = 3.5
=> BCNN(8, 12, 15) = 23.3.5 = 120
a, ab = 360 va BCNN[ a;b] = 60
b, UCLN[a:;b] =12 va BCNN[a;b] = 72
c, UCLN[a;b] = 15 va BCNN[a;b]=2100.UCLN[a;b]
tim bcnn 13 va 15
Tim hai so a va b biet tong cua BCNN va UCLN cua chung la 15.
Tim 2 so tu nhien a va b [a>b] co BCNN la 336 va UCLN la 12
tim hai so tu nhien a va b {a>b} co BCNN bang 336 va UCLN bang 12
tim BCNN cua a,b =300
UCLN cua a va b =15
tim 2 so tu nhien a va b biet rang BCNN;UCLN bang 15
Biet BCNN ( a,b ) = 60 va a = 12 .tim b
tim 2 so nguyen duong a;b biet 2a-3b=100 va 15. BCNN(a;b)+8. UCLN(a;b)=1950
lam nhanh giup minh nha !! thank you verry!!