`a) 5/9 - (1/3)^2= 5/9- 1/9= 4/9`
`b) 1/5. -3/2 + -17/2. 1/5= 1/5. (-3/2+-17/2)= 1/5.(-10)= -2`
`c) 1+ (-2/5 + 11/13) - (3/5- 2/13)= 1+ -2/5 + 11/13 + -3/5 + 2/13= 1+ (-2/5+ -3/5) + (11/13+2/13) =1+ (-1)+1=1`
A,=5/9-1/9
=4/9
B1/5.-3/2+-17/2.1/5
=1/5.[-3/2+(-17/2)]
=-10/2
C,=1+(-2/5-3/5)+(11/13+2/13)
1+(-1)+1
=1
A,=5/9-1/9
=4/9
B1/5.-3/2+-17/2.1/5
=1/5.[-3/2+(-17/2)]
=-10/2
C,=1+(-2/5-3/5)+(11/13+2/13)
1+(-1)+1
=1
a)5/9-(1/3)^2=4/
b)1/5×-3/2+-17/2×1/5=-2
c)1+(-2/5+11/13)-(3/5-2/13=1
a,5/9 -(1/3)^2
=5/9 -1/9
=4/9
b,1/5.-3/2+-17/2.1/5
=1/5.(-3/2-17/2)
=1/5.(-20/2)=1/5.(-10)=10/5=2
c,1+(-2/5+11/13)-(3/5-2/13)
=1-2/5+11/3-3/5+2/3
=1+(-2/5-3/5)+(11/13+2/13)=1+(-1)+1=1
a. 5/9-(1/3)2=5/9-1/9=4/9
b. 1/5.-3/2+-17/2.1/5 = 1/5. (-3/2+-17/2) = 1/5.-10 = 2
c. 1+(-2/5+11/13)-(3/5-2/13) = 1+-2/5+11/13-3/5+2/13 = 1+(-2/5-3/5)+(11/13+2/13) = 1+(-1)+1=1
a)\(\dfrac{5}{9}-\left(\dfrac{1}{9}\right)=\dfrac{5-1}{9}=\dfrac{4}{9}\)
b)\(\dfrac{1}{5}.\left(\dfrac{-3}{2}+\dfrac{-17}{2}\right)=\dfrac{1}{5}.\left(-10\right)=-2\)
c)\(1+\dfrac{29}{65}-\dfrac{29}{65}=\dfrac{94}{65}-\dfrac{29}{65}=1\)
a)5/9-(1/9)=4/9
b)1/5.(-3/2+-17/2)=1/5.(-10)=-2
c)1+(-2/5+11/13)-(3/5-2/13)=1+(-2/5)+11/13-(-3/5)+2/13
4/5=1
a,5/9-(1/3)^2=5/9-1/9=4/9
b,1/5.-3/2+-17/2.1/5=1/5.(-3/2+-17/2)=1/5.-10=-2
c,1+(-2/5+11/13)-(3/5-2/13)=1+-2/5+11/13-3/5+2/13=1+(-2/5-3/5)+(11/13+2/13)=1+-1+1=1
a) 5/9 - (1/3)2 = 5/9 - 1/9 = 4/9
b) 1/5 . -3/2 + -17/2 . 1/5 = 1/5.(-3/2 + -17/2) = 1/5 . -20/2 = 1/5 . -10 = -10/5 = -2
c) 1 + (-2/5 + 11/13) - (3/5 - 2/13) = 1 + (-2/5) + 11/13 - 3/5 + 2/13 = 1 + (-2/5 - 3/5) + (11/13 + 2/13) = 1 + (-1) + 1 = 1
`a) 5/9 - (1/3)^2= 5/9- 1/9= 4/9`
`b) 1/5. -3/2 + -17/2. 1/5= 1/5. (-3/2+-17/2)= 1/5.(-10)= -2`
`c) 1+ (-2/5 + 11/13) - (3/5- 2/13)= 1+ -2/5 + 11/13 + -3/5 + 2/13= 1+ (-2/5+ -3/5) + (11/13+2/13) =1+ (-1)+1=1`
a) 5/9 - (1/3)2 b)1/5 . -3/2 + -17/2 . 1/5 c) 1+ (-2/5+11/13) - (3/5 - 2/13)
= 5/9 - 1/9 = 1/5 . (-3/2 - 17/2) = 1+ (-2/5) + 11/13 - 3/5 + 2/13
= 4/9 = 1/5 . (-10) = 1+(-2/5-3/5) + ( 11/13 + 2/13)
= -2 = 1+ (-1) +1
= 1