\(\frac{1994.1993-2}{1992+1992.1994}=\frac{1994.1992+1994-2}{1992+1992.1994}=\frac{1994.1992+1992}{1992+1992.1994}=1\)
\(\frac{1994.1993-2}{1992+1991.1994}\)
= \(\frac{1994.1992-1994-2}{1992-1992.1994}\)
= \(\frac{1994.1992-1992}{1992-1992.1994}\)
= \(1\)
\(\frac{4}{5×8}+\frac{4}{8×11}+\dots+\frac{4}{47×50}\)