\(E=\left|x-3\right|+\left|x^2+1\right|-x\left(x-1\right)\)
th1: \(x-3\ge0\Leftrightarrow x\ge3\)
\(\Rightarrow\left|x-3\right|+\left|x^2+1\right|-x\left(x-1\right)=x-3+x^2+1-x^2+x=2x-2\)
th2: \(x-3< 0\Leftrightarrow x< 3\)
\(\Rightarrow\left|x-3\right|+\left|x^2+1\right|-x\left(x-1\right)=3-x+x^2+1-x^2+x=4\)
vậy \(E=2x-2;E=4\)